GATE Overflow Test Series | Programming | Test 1 | Question: 8

Question

What will be the output of the following C program?

#include<stdio.h>
struct my_struct
{
    int field1;
    float field2;
    double field3;
};
int main()
{
    struct my_struct try1, try2;
    try1.field1 = 10.1;
    try1.field2 = 10.1;
    try1.field3 = 10.1;
    try2 = try1;
    printf("%d %.1f %.1lf",
    try2.field1, try2.field2, try2.field3);
} 

• A. $10\; 10.1\; 10.1$
• B. $10.1\; 10.1\; 10.1$
• C. Possible Runtime Error
• D. Garbage Value 

Answer 1

.1f just means print only one digit after ".".
Here, 2 struct objects are created and "try2 = try1" copies all values of try1 to try2.

When a double value is assigned to an integer it automatically gets converted to an integer. So, "try1.field1 = "10.1" assigns "10" to field1. (Any fractional constant is by default taken as double unless it has an "f" suffix).

Correct Answer: A

Comments

sir how memory allocation happen here without malloc? I checked this one is working fine in compilers but am not getting how memory is assigned without malloc, please help. Thanks

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@prkshprasad1 See this.
https://stackoverflow.com/questions/10916799/how-to-create-a-struct-on-the-stack-in-c