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maximum no. Of edges 26

In a connected planner graph with v vertices e edges r regions or faces and min. Degree of region =k (no cycle of length less than 4 means no region can have degree less than 4)

The following property should satisfy

1 v-e+r=2

2 k.r≤2e

3 e ≤ k(v-2)/(k-2)

Here k=4 v=15

maximum no. Of edges

e ≤ 2v-4

Max no. Of edges= 2*15-4= 26

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e<=2v --4

so e<=2*15-4

e<=26
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Use following lemma for planer graph,

If G = (V, E) is a planar graph with |E| ≥ g and no cycle of length < g,

then: |E| ≤ (g /(g − 2)) (|V | − 2).

Here g = 4;  hence |E| ≤ (4 /(4 − 2)) (15 − 2)  = 26.

|E| ≤ 26 => Maximum no.of edges  = 26.

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