Each $150$ instructions require $8$ clock cycles.
This means total number of microinstructions $=150\times 8 = 1200$
We will need $\left\lceil \log_2 1200 \right\rceil = 11$ bits to address them.
Horizontal microprogramming means we will use a separate bit for each of the control signals.
So, size of control word = $132 + 11 = 143$ and control address register size $= 11$ bits.