0 votes 0 votes True/False Question : Suppose $a, b, c$ are positive real numbers such that $$\left ( 1+a+b+c \right )\left ( 1+\frac{1}{a}+\frac{1}{b}+\frac{1}{c} \right )=16.$$ Then $a+b+c=3.$ TIFR tifrmaths2017 true-false + – soujanyareddy13 asked Aug 30, 2020 edited Sep 30, 2020 by soujanyareddy13 soujanyareddy13 167 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.