Let $d$ be Draining Rate, $p$ be Pumping Rate and $L$ be the capacity of the tank.
$$\begin{align}
30 \times d &= \frac L 2\\[1em]
(10 \times p) - (10 \times d) &= \frac L 2\\[1em]
\implies\\[1em]
10 \cdot (p-d) &= 30\cdot d\\[1em]
p - d &= 3\cdot d \\[1em]
p &= 4\cdot d
\end{align}$$
Hence, option A is the correct answer.