A complete graph with $n$ vertices is $n-$chromatic, because all its vertices are adjacent. So, $\chi(K_{n}) = n.$
For coloring bipartite graphs, only two colors are needed. Hence, $\chi(K_{m,n}) = 2$.
A cyclic graph $C_n$ of odd order has $\chi(C_{2n+1})=3$, and that of even order has $\chi(C_{2n})=2.$ (A cyclic graph of even order is also bipartite.)
So, the correct answer is $(D)$.