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If three points are randomly chosen along the circumference of a unit circle, dividing the circle into three arcs, the expected length of the arc that contains the point $(1, 0)$ will be ____

  1. $\frac{\pi}{3}$
  2. $\frac{2\pi}{3}$
  3. $\pi$
  4. $\frac{\pi}{2}$

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Lets break this circle and make it a straight line of length $2\pi$ at the point $(1,0).$  Now, $(1,0)$ is present at both ends and if we choose $3$ random points along this line, we are dividing this line into $4$ parts with all their lengths equally likely to be $\frac{2\pi}{4}.$ Since, two of the parts are favorable, our required expectation will be $\dfrac{1}{4} \times 2 \times 2\pi = \pi.$
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