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Total number of outcomes $=6^6.$

Favorable cases are the ones without repetition. For $6$ rolls we can have $6\times 5 \times 4 \times 3 \times 2 \times 1 = 6!=720$ favorable cases.

So, required probability, $X=\dfrac{720}{6^6} = 0.01543 $

$1000X = 15.43$
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A die is rolled 6 times so total outcomes = 6^6

favorable outcomes without repetition(different number)= 6! = 6x5x4x3x2x1

So according to given scenario Probability = favorable outcomes without repetition/total outcomes

                                                                     = 6!  / 6^6

                                                                     =  0.01543

                                             so 1000X=  0.1543  x 1000 = 15.43

 

I hope my answer helps you a lot.

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