4 votes 4 votes For $L=\{\varepsilon \},$ if the number of total and final states required in the minimal state deterministic finite automata to accept $L$ over $\Sigma = \{a,b\}$ are denoted by $a$ and $b$ respectively, then $a-b = $_____ Theory of Computation go2025-toc-1 numerical-answers regular-expression finite-automata + – gatecse asked Sep 29, 2020 gatecse 376 views answer comment Share Follow See all 2 Comments See all 2 2 Comments reply theredeepakb commented Dec 21, 2021 reply Follow Share I think there is ambiguity in the questions 0 votes 0 votes Arjun commented Dec 21, 2021 reply Follow Share What ambiguity? 0 votes 0 votes Please log in or register to add a comment.
Best answer 4 votes 4 votes We need one initial state which is also the final state and one additional dead state. So, $2-1=1.$ So, the correct answer is $1.$ gatecse answered Sep 29, 2020 • selected Sep 26, 2021 by Arjun gatecse comment Share Follow See all 7 Comments See all 7 7 Comments reply Show 4 previous comments srestha commented Oct 14, 2020 reply Follow Share But here it is not mentioned , if there exists any alphabet for this language L. Then cannot be DFA and NFA same? 1 votes 1 votes rojee commented Oct 16, 2020 reply Follow Share yes! i have the same doubt, as it is clearly mentioned L={ε} then why others are considering presence of extra alphabets in L 1 votes 1 votes gatecse commented Oct 16, 2020 reply Follow Share Yes, Alphabet set should have been specified. Fixed now. 3 votes 3 votes Please log in or register to add a comment.
3 votes 3 votes . so, 2-1=1 MANSI_SOMANI answered Oct 13, 2022 MANSI_SOMANI comment Share Follow See all 0 reply Please log in or register to add a comment.