edited by
10,459 views
3 votes
3 votes

The volume generated by revolving the area bounded by parabola y^2 = 8x and the line x = 2 about y-axis is....

A) 128π/5

B) 5/128π

C) 127/5π

D) None

EDIT: Following is the area we have to revolve. And answer is given as (A). And kindly explain the methodology to solve such volumetric qstns if you get the answer. Thanx in advance :)

edited by

2 Answers

Best answer
7 votes
7 votes

I think I get it correct

selected by
0 votes
0 votes
I guess it is D).

$\int_{0}^{4}\Pi \left ( 2-y^{2}/8 \right )^{2}dy = 128\Pi /15$

Related questions

3 votes
3 votes
1 answer
1
28 votes
28 votes
4 answers
2
gatecse asked Feb 14, 2018
16,009 views
The value of $\int^{\pi/4} _0 x \cos(x^2) dx$ correct to three decimal places (assuming that $\pi = 3.14$) is ____
1 votes
1 votes
0 answers
3