With $A_{1}$ as candidate key, the number of super keys, $SK(A_{1}) = 2^{4}$ (any subset of the remaining $4$ attributes including the empty set form a super key.
Similarly with $A_{2}$ as candidate key, the number of super keys, $SK(A_{2}) = 2^{4}$
And with $\{A_{1}A_{2}\}$ as candidate key the number of super keys, $SK(A_{1}A_{2}) = 2^{3}.$
Now, the total number of distinct super keys $SK(A_{1}A_{2}) = SK(A_{1}) + SK(A_{2}) - SK(A_{1}A_{2})$
$\qquad = 2^{4} + 2^{4} - 2^{3} = 16 + 16 – 8 = 32 – 8 = 24.$
So, the correct answer is $24.$