Except for $\text{count}(^{\ast}) ,$ aggregate functions ignore null values.
Now, $\text{sum(A) } = 6, \text{avg(A)} = \dfrac{6}{3} = 2,\text{sum(B) } = 1, \text{avg(B)} = \dfrac{1}{1} = 1.$
$\therefore \text{sum(A) } + \text{avg(A)} + \text{sum(B) } + \text{avg(B)} = 6 + 2 + 1 + 1 = 10.$
So, the correct answer is $10.$