Probability that the bulb lasts either more than $200$ hours or less than $50$ hours. $P = P(x > 200) + P( x \leq 50)$
$\qquad = P(x > 200) + 1 - P( x > 50)$
$\qquad = e^{-200\lambda} + 1 - e^{-50 \lambda}$
Here, $\lambda = \frac{1}{100}.$
So, $P = e^{-2} + 1 - e^{-0.5} =0.5288$