GATE Overflow Test Series | Computer Networks | Test 1 | Question: 7

Question

Which of the following mapping is CORRECT with respect to $IPv4$?

$$\begin{array}{|c l |c l |}
\hline
& \text{Destination Address} & &\text{Type}
\\\hline
\text{I} & \text{01:00:5E:32:10:2C} & \text{a}&\text{Broadcast Address}\\\hline
\text{II} & \text{2C:22:15:13:54:C2} & \text{b}&\text{Multicast Address}\\\hline
\text{III} & \text{FF:FF:FF:FF:FF:FF} & \text{c}&\text{Unicast Address}
\\\hline
\end{array}$$

• A. $\text{I – b, II – c, III – a}$
• B. $\text{I – c, II – b, III – a}$
• C. $\text{I – a, II – c, III – b}$
• D. None of the above

Answer 1

The multicast $MAC$ address is a special value that begins with $01-00-5E$ in hexadecimal. The remaining portion of the multicast $MAC$ address is created by converting the lower $23$ bits of the $IP$ multicast group address into $6$ hexadecimal characters.

Comments

sir can you give some link for this i am not getting this concept?? Thanks

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@Sharma9999999

Please go to the below link and scroll down to the types of Mac Address, nicely explained in this link, hope this will help.

 

https://www.computernetworkingnotes.com/ccna-study-guide/mac-addresses-explained-with-examples.html

 

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It can be determined by observing 8^th bit from MSB (ie last bit of first octet)

if this bit = 1, MULTICASTING

if this bit = 0, UNICASTING

 

FF:FF:FF:FF:FF:FF is BROADCAST ADDRESS