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Let $A$, $B$ and $C$ be three pipes, then according to question

Part of tank which three of them fills in $1$ hr = $ \frac{1}{A} + \frac{1}{B}+ \frac{1}{C} =\frac{1}{4}$

Similarly $\frac{1}{A}= 8, \frac{1}{B}= 12$ then 

$\frac{1}{C} = \frac{1}{4}- (\frac{1}{8}+\frac{1}{12})$

$\frac{1}{C}= \frac{1}{24}$

Option D) is correct

Answer:

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