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A non-pipeline system takes $50$ns to process a task. The same task can be processed in six-segment pipeline with a clockcycle of $10$ns. Determine approximately the speedup ratio of the pipeline for $500$ tasks.

  1. $6$
  2. $4.95$
  3. $5.7$
  4. $5.5$
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time for non pipeline system  1 task =50 ns  500 tasks =500x50 =25000 ns

time with k(=6) segment pipeline      first task 6x10 ns  subsequent task =10 ns  so 499x10 =4990

              total =60+4990=5050

Speedup ratio = time taken without pipeline / time with pipeline

                      =25000/5050 =4.95

hence option 2) is the right ans

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