1 votes 1 votes Consider a machine with a byte addressable main memory of $2^{16}$ bytes block size of $8$ bytes. Assume that a direct mapped cache consisting of $32$ lines used with this machine. How many bits will be there in Tag, line and word field of format of main memory addresses? $8,5,3$ $8,6,2$ $7,5,4$ $7,6,3$ CO and Architecture ugcnetcse-oct2020-paper2 co-and-architecture cache-memory + – go_editor asked Nov 20, 2020 • recategorized Nov 25, 2020 by Krithiga2101 go_editor 3.6k views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
5 votes 5 votes Physical address = $16$ bits Block Size= $8B$, word offset= $3$ bits Number of blocks in cache = $32$, cache offset = $5$ bits TAG bits= $16-5-3=8$ bits Option A) is correct Ashwani Kumar 2 answered Nov 20, 2020 Ashwani Kumar 2 comment Share Follow See all 0 reply Please log in or register to add a comment.
