3 votes 3 votes The number of positive integers not exceeding $100$ that are either odd or the square of an integer is _______ $63$ $59$ $55$ $50$ Set Theory & Algebra ugcnetcse-oct2020-paper2 discrete-mathematics inclusion-exclusion + – go_editor asked Nov 20, 2020 recategorized Nov 24, 2020 by Krithiga2101 go_editor 3.4k views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
3 votes 3 votes Required numbers = n(Odd numbers) + n(Square of integers) – n(odd number & square of integer) From $1$ to $100$ there are $50$ odd and $50$ even numbers Square of integers = $1,4,9,16,25,64,49,64,81,100$ = $10$ numbers Both odd & square of integer= $1,9,25,49,81 = 5$ numbers Hence required numbers= $50+10-5 = 55$ Ashwani Kumar 2 answered Nov 20, 2020 Ashwani Kumar 2 comment Share Follow See all 0 reply Please log in or register to add a comment.
1 votes 1 votes total number=100 odd=even=total/2=100/2=50 square number=1,4,9,16,25,36,49,64,81,100 total square number=10 odd and square =1,9,25,49,81 required number=50+10-5 ans=55 sawanKumar answered Jan 15, 2021 sawanKumar comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes Number of odd numbers between 1 and 100 is 50 and even squares are 4,16,36,64,100 so the answer is 55 for this. eshita1997 answered Jan 6, 2021 eshita1997 comment Share Follow See all 0 reply Please log in or register to add a comment.