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In the waveform (a) given below, a bit stream is encoded by Manchester encoding scheme. The same bit stream is encoded in a different coding scheme in wave form (b). The bit stream and the coding scheme are

  1. $1000010111$ and Differential Manchester respectively
  2. $0111101000$ and Differential Manchester respectively
  3. $1000010111$ and Integral Manchester respectively
  4. $0111101000$ and Integral Manchester respectively
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Correct answer A

If u take option A bit stream and make dman it will match 

If u take option B bit stream u will get this:-

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Answer: (A)

Explanation: In simple language, Manchester encoding has +A to -A transition for the clock cycle for which bit is ‘1’ and transition from -A to +A for the cycle when bit is ‘0’ (A is the amplitude).

kriti_9

kriti_10

The amplitudes are bipolar in Differential manchester encoding same as manchester encoding just that it toggles at ‘1’. When bit is ‘1’ we get transition from +A to -A and it remains the same until next ‘1’ arrives. The output changes to opposite transition (-A to +A) when next ‘1’ arrives.
The second encoding resembles the differential manchester code for the given number.

Answer:

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