GATE Overflow Test Series | Operating Systems | Test 2 | Question: 16

Question

In a virtual memory system, size of the virtual address is $\text{64-bit}$, size of the physical address is $\text{60-bit},$ page size is $4\;\text{Kbyte}$ and size of each page table entry is $\text{64-bits}.$ The main memory is byte addressable. The maximum number of bits that can be used for storing protection and other information in each page table entry is _______

Answer 1

Number of physical address bits needed to address a page frame $ = 60 - 12 = 48.$

Since, PTE is $64$ bits we have $64 - 48 = 16$ bits for other information.