3 votes 3 votes Consider a $\text{8-TB}$ disk that uses $\text{2-KB}$ blocks and the free-list method. The number of block addresses that can be stored in one block will be _______ Operating System go2025-os-2 numerical-answers file-system file-organization + – gatecse asked Dec 7, 2020 • edited Dec 7, 2020 by Lakshman Bhaiya gatecse 424 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
2 votes 2 votes The number of blocks on the disk $= 8 TB / 2 KB = 2^{32}.$ Therefore, each block address need to be $32 \:\text{bits}\: (4\:\text{bytes})$ Now, each block can store $2 KB/4 = 512$ addresses. gatecse answered Dec 7, 2020 • edited Nov 6, 2021 by Arjun gatecse comment Share Follow See all 0 reply Please log in or register to add a comment.
