$\textrm{option d}$

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since it is class B address we have 16 bits for net & 16 bits for host id

to accommodate 600 host per subnet we need 10 bits (2^10= 1024 as 2^9 =512 will not hold in this scenario)

therefore we need to make rightmost 10 bits as 0 for mask and rest 22 will be as 1 which is nothing but

11111111.11111111.11111100.00000000

255.255.252.0

therefore option C

to accommodate 600 host per subnet we need 10 bits (2^10= 1024 as 2^9 =512 will not hold in this scenario)

therefore we need to make rightmost 10 bits as 0 for mask and rest 22 will be as 1 which is nothing but

11111111.11111111.11111100.00000000

255.255.252.0

therefore option C