1 votes 1 votes If main memory access time is $400\;\mu s$, $TLB$ access time $50\;\mu s$, considering $TLB$ hit $90\%$, what wil be the overall access time? $800\;\mu s$ $490 \;\mu s$ $485\;\mu s$ $450\;\mu s$ Unknown Category nielit-scb-2020 + – gatecse asked Dec 9, 2020 • edited Dec 12, 2020 by soujanyareddy13 gatecse 368 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes EMAT $=$ TLB hit $\times$ (TLB access time $+$ memory access time) $+$ TLB miss(TLB access time $+$ page table access time+memory access time) $\implies$ EMAT $ = \dfrac{90}{100}(50+400) + \dfrac{10}{100}(50 + 400 + 400) \:\mu s$ $\implies $ EMAT $ = \dfrac{9}{10}(450) + \dfrac{1}{10}(850)\:\mu s$ $\implies $ EMAT $ = 9 \times 45 + 85 \:\mu s = 405 + 85 \:\mu s = 490\:\mu s.$ Ref: https://gateoverflow.in/2067/gate2014-3-33 So, the correct answer is $(B).$ Lakshman Bhaiya answered Dec 10, 2020 Lakshman Bhaiya comment Share Follow See all 0 reply Please log in or register to add a comment.