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NIELIT Scientist B 2020 November: 51

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Modulation Index $(m)=\dfrac{V_m}{V_c}$

$V_m =$ modulation amplitude,$V_c =$ carrier amplitude signal

$\implies m=\frac{8}{12} \times 100\% = 66.66\%$

$\implies m \approx67\%$

Option $(B)$ is correct.
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