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We have $6$ parts in the fold. When completely folded  we get the following opposite pairs $(\Phi,\Gamma),$ $(\Psi,\Omega)$ and $(\Pi,\Lambda).$

If we take $\Phi$ and $\Gamma$ as top and bottom, then the other sides will be $\Pi, \Psi, \Lambda, \Omega.$

Since we are free to rotate the cube or flip it, any combination of pairs is possible except the opposite pairs coming adjacent.

In option C, opposite pairs $(\Psi,\Omega)$ are coming adjacent which is not possible.

For $A, B$ and $D$ no opposite pairs are adjacent and hence they are possible when the given figure is folded.

So, the correct answer is $A;B;D.$
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