We have $6$ parts in the fold. When completely folded we get the following opposite pairs $(\Phi,\Gamma),$ $(\Psi,\Omega)$ and $(\Pi,\Lambda).$
If we take $\Phi$ and $\Gamma$ as top and bottom, then the other sides will be $\Pi, \Psi, \Lambda, \Omega.$
Since we are free to rotate the cube or flip it, any combination of pairs is possible except the opposite pairs coming adjacent.
In option C, opposite pairs $(\Psi,\Omega)$ are coming adjacent which is not possible.
For $A, B$ and $D$ no opposite pairs are adjacent and hence they are possible when the given figure is folded.
So, the correct answer is $A;B;D.$