$1 \times 2 \times 3 \times 4 \times 5 \times 6 \times 7 = 7! = 5040,$ it divides the product of seven consecutive integers.
Now, if we take any $7$ consecutive integers, it'll have a multiple of numbers from $2-7$. That means any consecutive sequence of integers will be a multiple of $5040.$
So, the correct answer is $(A).$