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Which among the following integers is the largest one that divides the product of any seven consecutive integers?

  1. $5040$
  2. $40320$
  3. $510510$
  4. $201600$
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$1 \times 2 \times 3 \times 4 \times 5 \times 6 \times 7 = 7! = 5040,$ it divides the product of seven consecutive integers.

Now, if we take any $7$ consecutive integers, it'll have a multiple of numbers from $2-7$. That means any consecutive sequence of integers will be a multiple of $5040.$

So, the correct answer is $(A).$
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