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GATE Overflow Test Series | Calculus | Test 1 | Question: 11

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$\displaystyle \lim_{x \to 0} x = 0$

Since,  $-1 \le \sin{\frac{1}{x}} \le 1$ given limit

$\qquad \displaystyle = 0 \times  \sin{\frac{1}{x}} = 0.$
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