GATE Overflow Test Series | Mock GATE | Test 1 | Question: 35

Question

Consider the following C Code

#include<stdio.h>
int main()
{
   int i=0;
   do
   {
       do
       {

          while(i++<2);

       }while(i++<4);

   }while(i++<=9);

   printf("%d",i++);

   return 0;
}
   

What will be the output of the above program?

• A. $13$
• B. $11$
• C. $12$
• D. $10$

Answer 1

We can do that, in this way.

• $i = 0<2\; \checkmark$
• $i = 1<2\; \checkmark$
• $i = 2<2$
• $i = 3<4\; \checkmark$
• $i = 4<2$
• $i = 5<4$
• $i = 6\leq 9\; \checkmark$
• $i = 7<2$
• $i = 8<4$
• $i = 9\leq 9\; \checkmark$
• $i = 10<2$
• $i = 11<4$
• $i = 12\leq 9$
• $ i = 13$

printf("%d",i++);

$\therefore i = 13$ is printed, and at last $i = 14.$

So, the correct answer is $(A).$

Comments

@Lakshman Patel RJIT after checking 5<4 , innermost loop can not run, because mid loop will false..