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For the quadratic equation $ax^2+bx+c=0$,

the sum of it’s root =$-\frac{b}{a}$,

product of it’s root= $\frac{c}{a}$

compair the equation $9x^2+171x-81$ with standred equation,we get:

$a=9$

$b=171$

$c=-81$

$\therefore$ sum of root=$-\frac{171}{9}=-19$

product of root= $-\frac{81}{9}=-9$

Option A is correct.
Answer:

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