For the quadratic equation $ax^2+bx+c=0$,
the sum of it’s root =$-\frac{b}{a}$,
product of it’s root= $\frac{c}{a}$
compair the equation $9x^2+171x-81$ with standred equation,we get:
$a=9$
$b=171$
$c=-81$
$\therefore$ sum of root=$-\frac{171}{9}=-19$
product of root= $-\frac{81}{9}=-9$
Option A is correct.