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Suppose you roll two six-sided fair dice with faces numbered from $1$ to $6$ and take the sum of the two numbers that turn up. What is the probability that:

  • the sum is $12;$
  • the sum is $12$, given that the sum is even;
  • the sum is $12$, given that the sum is an even number greater than $4$?
  1. $\frac {1}{36}, \frac {1}{18} $, and $\frac {1}{12}$, respectively
  2. $\frac {1}{36}, \frac {1}{18} $, and $\frac {1}{14}$, respectively
  3. $\frac {1}{36}, \frac {1}{16} $, and $\frac {1}{14}$, respectively
  4. $\frac {1}{36}, \frac {1}{16} $, and $\frac {1}{12}$, respectively
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