By A.M-G.M inequality we know that $\frac{a_1+a_2+\dots +a_n}{n}\geq \sqrt[n]{a_1 a_2 \dots a_n}$
Therefore we have $\frac{a+b+c+d}{4}> \sqrt[4]{abcd}$ and $\frac{u+v+w+x}{4}> \sqrt[4]{uvwx}$.
[ Note: since a,b,c,d are not all equal therefore equality does not hold in this case]
Multiplying these inequalities $(a+b+c+d)(u+v+w+x)>16\sqrt[4]{abcduvwx}=16$
Therefore we got option A is true