6 votes 6 votes In how many ways can we choose $3$ numbers one after other from the set $\{1, 2, 3, 4, 5, 6, 7\}$ so that the numbers chosen are in increasing order? $\binom{7}{3}$ $\binom{7}{3} / 3!$ $^{7}P_3$ None of the above Combinatory go2025-mockgate-5 combinatory counting 1-mark + – gatecse asked Feb 8, 2021 • recategorized Feb 8, 2021 by soujanyareddy13 gatecse 381 views answer comment Share Follow See 1 comment See all 1 1 comment reply JayRathi commented Jan 28 reply Follow Share @Deepak Poonia sir here repetition also possible na this is IODB template answer should be 9C3. 0 votes 0 votes Please log in or register to add a comment.
Best answer 6 votes 6 votes The number of ways to choose $r$ items from $n$ items where there is only one possible ordering is $\binom{n}{r}.$ So, $\binom{7}{3}$ is the answer. gatecse answered Feb 8, 2021 • selected Jan 15, 2022 by Arjun gatecse comment Share Follow See all 0 reply Please log in or register to add a comment.