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In how many ways can we choose $3$ numbers one after other from the set $\{1, 2, 3, 4, 5, 6, 7\}$ so that the numbers chosen are in increasing order?

  1. $\binom{7}{3}$
  2. $\binom{7}{3} / 3!$
  3. $^{7}P_3$
  4. None of the above
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The number of ways to choose $r$ items from  $n$ items where there is only one possible ordering is $\binom{n}{r}.$ So, $\binom{7}{3}$ is the answer.
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