1 votes 1 votes The number of Clock pulses needed to change the contents of an 8-bit-up-counter from (10101011) to (00111010) is ______________ Digital Logic made-easy-test-series digital-logic digital-counter + – Akanksha Kesarwani asked Jan 14, 2016 • edited Mar 5, 2019 by akash.dinkar12 Akanksha Kesarwani 1.0k views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
Best answer 2 votes 2 votes $171 \rightarrow 255 \rightarrow 58 = 84+59 = 143$ amarVashishth answered Jan 14, 2016 • selected Jan 9, 2017 by Akanksha Kesarwani amarVashishth comment Share Follow See all 2 Comments See all 2 2 Comments reply Akanksha Kesarwani commented Jan 14, 2016 reply Follow Share Ans given is 41.40 0 votes 0 votes Praveen Saini commented Jan 14, 2016 reply Follow Share $10101011= 171$ $00111010 = 58$ $8$-bit up counter means it is mod$256$ counter, we are at $171$ clock pulse , clock pulses we need to reach initial state is $256-171=85$ clock pulses , we need $58$ more clock pulses to reach $00111010$ $85+58 = 143$ 2 votes 2 votes Please log in or register to add a comment.