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Given answer is 101 but I am getting 35. Please check.

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$(3)_4+(2)_4 =(5)_{10} =(11)_4$, that will give one carry. 

Now, carry, $(1)_4+(2)_4+(1)_4=(4)_{10}=(10)_4$

So, on adding we get,   $(2.3)_4+(1.2)_4=(10.1)_4 $

$(10.1)_4 \times (10)_4=(101)_4$

Or, Another way is to convert them in decimal, then after doing all calculation, convert back to desired base. 

Note: In base $4$, we can only {$0,1,2,3$}, in any calculation(adding or multiplication)  if get $4$ or above. It need to convert back into base $4$

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Convert into binary then add  and again convert to 4 base with multiplication with 10

(2.3)+ (1.2)4 =>  (01.11)2+ (01.10)2  => (0100.01)2  =>  (10.1)

(10.1)4 *10 = (101)4     Solved

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(2.3)4 +(1.2)4 =(10.1)4 =(Y)4

Y  converted  in base 10

(10.1)4 =  1*4+0*1+1/4  = 4 + 0.25 = 4.25

Then Y*10 is 4.25 * 10=  (42.5)10

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