2 votes 2 votes They have taken 1 extra combination which is already a subset of 2 other combos. Is it because that they have asked ALL POSSIBLE k-maps??? Is it right? Digital Logic ace-test-series digital-logic k-map + – Tushar Shinde asked Jan 14, 2016 edited Mar 6, 2019 by akash.dinkar12 Tushar Shinde 891 views answer comment Share Follow See all 5 Comments See all 5 5 Comments reply Show 2 previous comments monanshi commented Jan 15, 2016 reply Follow Share yes you are correct..it should be ACD.. But...ABC' + A'C'D + A'BC + ACD + AB'C + BD = 17 literals... why you are not considering ACD here..? 1 votes 1 votes Digvijay Pandey commented Jan 15, 2016 reply Follow Share ABC' + A'C'D + A'BC + AB'C + BD check every min term is in given expression or not ?? if yes then what is the use of redundant ACD ?? 1 votes 1 votes Tushar Shinde commented Jan 15, 2016 reply Follow Share Yes, as last 2 terms in . ABC' + A'C'D + A'BC + AB'C + BD will make ACD redundant as per consensus theorem. B'AC + BD + ACD = B'AC + BC 1 votes 1 votes Please log in or register to add a comment.
3 votes 3 votes No it is 14 only.. 1 Quad and 3 Pair. ABC' + A'C'D + A'BC + AB'C + BD Digvijay Pandey answered Jan 14, 2016 Digvijay Pandey comment Share Follow See 1 comment See all 1 1 comment reply Registered user 7 commented Jan 21, 2016 reply Follow Share 1 quad 4 pairs 0 votes 0 votes Please log in or register to add a comment.
0 votes 0 votes 14 is right . abhishekmehta4u answered Mar 6, 2019 abhishekmehta4u comment Share Follow See all 0 reply Please log in or register to add a comment.