retagged by
777 views

1 Answer

Best answer
4 votes
4 votes
We can write, the unit’s place in $26591749^{110016} = $ the unit’s place in $9^{110016}$

Now, we know that the unit place of  $9^{1} = 9,9^{2} = 1,9^{3} = 9,\ldots$

$\therefore$ The cyclicity of $9$ is $2.$

And, $110016$ is divisible by $2,$ so the unit place of $9^{2} = 1.$

$\text{(Or)}$

The unit place of $9^{\text{odd}} = 9,9^{\text{even}} = 1.$

The number $110016$ is even, so the unit place of $9^{\text{even}} = 1.$

So, the correct answer is $(A).$
selected by
Answer:

Related questions

3 votes
3 votes
3 answers
1
go_editor asked Feb 27, 2020
674 views
The sum of two positive numbers is $100$. After subtracting $5$ from each number, the product of the resulting numbers is $0$. One of the original numbers is ______.$80$...
5 votes
5 votes
7 answers
2
go_editor asked Feb 27, 2020
2,047 views
Insert seven numbers between $2$ and $34$, such that the resulting sequence including $2$ and $34$ is an arithmetic progression. The sum of these inserted seven numbers...
3 votes
3 votes
1 answer
3
go_editor asked Feb 27, 2020
936 views
The total expenditure of a family, on different activities in a month, is shown in the pie-chart. The extra money spent on education as compared to transport (in percent)...
3 votes
3 votes
2 answers
4
gatecse asked Sep 18, 2019
710 views
The digit in the unit place of the number $7^{78}$ is$1$$3$$7$$9$