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A router uses the following routing table:

\begin{array}{|l|l|l|} \hline \textbf {Destination} & \textbf { Mask} & \textbf{Interface}  \\\hline \text {144.16.0.0} &  \text{255.255.0.0} & \text{eth$0$} \\\hline\text {144.16.64.0} &  \text{255.255.224.0} & \text{eth$1$} \\\hline\text {144.16.68.0} &  \text{255.255.255.0} & \text{eth$2$}\\\hline \text {144.16.68.64} &  \text{255.255.255.224} & \text{eth$3$}\\\hline\end{array}

 Packet bearing a destination address $144.16.68.117$ arrives at the router. On which interface will it be forwarded?

  1. eth$0$
  2. eth$1$
  3. eth$2$
  4. eth$3$
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–5 votes
–5 votes
Answer: D

Select the longest mask as the packet is eligible to be forwarded to all interfaces.
Answer:

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