Part 1(for S1)
Suppose there are three slot 1,2 and 3
Every station can send traffic only during one slot and in remaining two slots it will not send traffic(bcz on off duty cycle is 1:2)
Here we have to find minimum number of station that can generate traffic so that we have maximum utilization with no loss of data.
Any station can generate traffic during any slot But there is no buffer it means the traffic generated by stations during slot 1 will also be on link during slot2 and slot 3 also traffic generated by stations during slot 2 will also be on link during slot 3
But we have to find out minimum number of stations which will be possible when all stations generate traffic during same slot.
Traffic generated by n stations= Bandwidth
10*n=100
So n=10 stations
Alternate method for part 1(for S1)
Let n1,n2 and n3 be the no of stations that generate traffic during slot 1, slot 2 and slot 3 respectively.
Any station can generate traffic during any slot But there is no buffer it means the traffic generated by stations during slot 1 will also be on link during slot 2 and slot 3 also traffic generated by stations during slot 2 will also be on link during slot 3.
Traffic generated during slot 1 =n1*10
Traffic generated during slot 2 =n2*10
Total Traffic during slot 3 =n3*10 + n1*10 + n2*10.
Total traffic=100 Mbps
n3*10 + n1*10 + n2*10 =100
n3 + n1 + n2 =10
Part 2(For S2)
Suppose there are three slot 1,2 and 3
Every station can send traffic only during one slot and in remaining two slots it will not send traffic(bcz on off duty cycle is 1:2)
The stations who generate traffic during slot 1 their data during slot 2 and and during slot 3 can be stored in buffer.
The stations who generate traffic during slot 2 their data during slot 3 can be stored in buffer.
So lets's find how many maximum stations can send data during slot 1 so that we will have maximum utilization with no loss of data.
Let n station generate traffic during slot 1 as each station generate 10 Mbps.
So n station generate 10*n Mbps it must be equal to.100Mbps (for maximum utilization and no loss of data)
10n=100
So n=10 during slot 1.
It is also true for other slots also.
So Total Stations=10(slot1)+10(slot2)+10(slot3)=30.
Correct me if you think my approach is wrong.