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If $7\:\theta\: 13\: \alpha\: 3 = 60,$ and $12\:\theta\: 13\: \alpha\: 4 = 100,$ then $38\:\theta\: 39\: \alpha\: 3 =\:?$

  1. $313$
  2. $219$
  3. $343$
  4. $231$
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  • $(7+13)\times 3 = 20 \times 3 = 60$
  • $(12+13)\times 4 = 25 \times 4 = 100$
  • $(38+39)\times 3 = 77 \times 3 = 231$

So, the correct answer is $(D).$

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