Every job is distinct and person is also distinct
let jobs are = j1,j2,j3,j4,j5,j6,j7 (j1 is most difficult and j7 is easy)
person are = p1,p2,p3,p4 (p1 is best , p4 is least best)
as given j1 is handled by p1 only so we have only 5 jobs left(j2 to j7)
at lease one job done by each person will be like
total ways – every process not done by (p2 to p4, p1 is handling j1)
total ways = 4^6 ( each job(j2 to j7) has 4 possibility = 4096
every process not done by (p2 to p4) = all the jobs done by p1 = 1^6 = 1
total ways = 4096 – 1 = 4095