2 votes 2 votes $\lim_{x\rightarrow a} f(x)^{g(x)} = e^{\lim_{x\rightarrow a}g(x)[f(x)-1]}$ Solve the below limit without using the above formula, $\lim_{x \rightarrow 0} ({\frac{sin x}{x}})^{\frac{sin x}{x - sin x}}$ dutta007sourish asked Sep 7, 2021 dutta007sourish 319 views answer comment Share Follow See all 5 Comments See all 5 5 Comments reply Show 2 previous comments shuham kumar commented Sep 11, 2022 reply Follow Share my ansr is comming 0 0 votes 0 votes [ Jiren ] commented Sep 12, 2022 reply Follow Share @ankitgupta.1729 sir Can we say this is of the form 1^infinity as x tends to 0 0 votes 0 votes ankitgupta.1729 commented Sep 12, 2022 reply Follow Share yes. 0 votes 0 votes Please log in or register to add a comment.