1.) group with one Indian – 3C1(choose 1 Indian out of three) * 2^3 (for Chinese people, each Chinese have 2 possibility either he present in group or not) = 3 * 2^3 = 24
2.) group with 2 Indian = 3C2 * 2^3 = 24
3.) group with 3 Indian 3C3 * 2^3 = 8
total group with at least one Indian = 24 + 24 + 8 = 56
OR
Total Group – group without Indian
(2^6 – 1) – (2^3) = 56