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Consider the size of the congestion window of a TCP connection be 40 KB when a timeout occurs. The round trip time of the connection is 50 msec and the maximum segment size used is 2 KB. How much time it will be required(in milli sec) to reach the congestion window of 30 KB?

 

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Threshold = 40 / 2 = 20 KB

First transmission = 2 KB

Second transmission = 4 KB

Third transmission = 8 KB

Fourth transmission = 16 KB

Fifth transmission = 20 KB

Sixth transmission= 22 KB

Seventh transmission = 24 KB

Eight transmission = 26 KB

Ninth transmission=28 KB

 

A total of 9 RTTs are required to reach the congestion window of 30 KB.

9 RTTs  = 9 * 50 = 450 msec

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