1 votes 1 votes In a CDMA/CD network with a data rate of 20 Mbps, the maximum distance between station pair is found to be 2000 m then what is the minimum transmission time(in sec) for the network if the speed is 4 * 10 ^4 m/sec ? Computer Networks test-series computer-networks csma-cd ethernet data-link-layer + – LRU asked Oct 13, 2021 LRU 1.1k views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
Best answer 4 votes 4 votes In CSMA/CD, Transmission delay >= 2 * Propagation delay Tt >= 2 * 2000/(4 * 10^4) sec Tt >= 0.1 sec Aashay kaurav answered Oct 15, 2021 • selected Oct 15, 2021 by LRU Aashay kaurav comment Share Follow See all 0 reply Please log in or register to add a comment.