0 votes 0 votes Consider a disk with a sector size of 512 bytes, 1000 tracks per surface, 25 sectors per track, 5 double-sided platters, and average seek time of 10 msec. The capacity of tracks in bytes is _____ KB Operating System test-series operating-system disk + – LRU asked Oct 20, 2021 LRU 578 views answer comment Share Follow See 1 comment See all 1 1 comment reply Chandrabhan Vishwa 1 commented Oct 20, 2021 reply Follow Share here question telling about capacity of tracks = number of sector per track * sector size =12.5 KB 1 votes 1 votes Please log in or register to add a comment.
Best answer 1 votes 1 votes Given, Sector size – 512 bytes Number of double-sided disk platters - 5 Number of tracks per each side of each disk platter – 1000 Number of sectors per track – 25 Average seek time – 10 msec The capacity of track can be calculated as follows; Capacity of track = bytes/track = bytes/sector * sectors/track = 512 bytes/sector * 25 sectors/track = 12800 bytes = 12800/1024 KB = 12.5 KB Vishal_kumar98 answered Oct 21, 2021 • selected Dec 14, 2021 by LRU Vishal_kumar98 comment Share Follow See all 0 reply Please log in or register to add a comment.