0 votes 0 votes In the CSMA/CD network the bandwidth of the link is 10 Mbps, two stations are connected at both the ends of the link. The speed of the transmission on the links is 5 x 10 ^6 m/sec. What is the length of the link in kilometre, if the minimum frame size is 500 bytes ? Computer Networks test-series computer-networks data-link-layer + – LRU asked Oct 21, 2021 LRU 451 views answer comment Share Follow See all 2 Comments See all 2 2 Comments reply lalitver10 commented Oct 21, 2021 reply Follow Share TransmissionTime =Tt PropogationTime=Tp By Using Formula Tt>=2Tp ------>L\B>=2*d\v 500*8\10*10^6>2d\5*10^6 Answer --1km. 1 votes 1 votes LRU commented Oct 21, 2021 reply Follow Share Thanks 0 votes 0 votes Please log in or register to add a comment.
Best answer 1 votes 1 votes to detect the collision in signal path maximum 2* propagation time of frame length transmission required so overall frame length = RTT* bandwidth 500*8 bit=2*distance/velocity *bandwidth put the vale and after calculation distance =1km Chandrabhan Vishwa 1 answered Oct 21, 2021 • selected Oct 21, 2021 by LRU Chandrabhan Vishwa 1 comment Share Follow See all 0 reply Please log in or register to add a comment.
