here question telling about overall speed up
so here you take nonpipeline instruction taking 100 unit time then in this question the speedup only on the 40 percent of the time means here pipelined instruction 60 unit time same as nonpipeline and 40 unit time speedup so 40 time speed up by 10 then it is taking only 4 unit time so overall time in pipeline is 4+60=64
so overall speedup=ET old means nonpipeline/pipelined =100/64=1.5625