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What is the bit rate of a video terminal unit with $80$ characters/line, $8$ $\text{bits/character}$ and horizontal sweep time of $100$ $\text{µs}$ (including $20$ $\text{µs}$ of retrace time)?

  1. $8$ $\text{Mbps}$
  2. $6.4$ $\text{Mbps}$
  3. $0.8$ $\text{Mbps}$
  4. $0.64$ $\text{Mbps}$
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26 votes

Answer: (B)

Bit rate of a video terminal unit $= 80 \times 8$ bits$/100 µs = 6.4$ Mbps

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bit rate is the count of bits per second.

$80$ $characters$ =====>$100µsec$

$80\times 8$ $bits$======>$100µsec$

$640$ $bits$=======>$100µsec$

$1µsec$=======>$6.40$ $bits$

$1\times10^{-6}  sec$=====>$6.40$ $bits$

$1 sec$====>$6.40\times 10^{6}$ $bits$

   $bit$  $rate=6.40Mbps$

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