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Number of memory access

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Given answer is A.
I believe that B should be the answer because as the number of page tables are k. k memory access are required for each table and finally, one for accessing the data from main memory. Please check.

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if there is no page table then number of memory reference(s) to get date is ONE.
if K- PAGE TABLE are der (i.e. K-LEVEL PAGING) then number of memory references are (K+1)*m.

OVERHEAD = (K+1)*m - m = K*m
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